Given the moment of inertia of a disc of mass M and radius R about any of its diameters to be `MR^(2)//4`, find its moment of inertia about an axis normal to the disc and passing through a point on its edge.

Explanation

We are given, moment of inertia of the disc about any of its diameters = `(1)/(4)MR^(2)`.
i) Using theorem of perpendicular axes, moment of inertia of the disc about an axis passing through its center and normal to the disc `=2xx(1)/(4)MR^(2)=(1)/(2)MR^(2)`.
ii) Using theorem of parallel axes, moment of inertia of the disc passing through a point on its edge and normal to the disc `=(1)/(2)R^(2)+MR^(2)=(3)/(2)MR^(2)`.