The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm is 16 seconds.
What is its angular acceleration, assuming the acceleration to be uniform?

Explanation

We shall use `omega=omega_(0)+alphat`
`omega_(0)` = initial angular speed in rad/s
`=2pixx` angular speed in rev/s
`=(2pixx"angular speed in rev/min")/("60s/min")`
`=(2pixx1200)/(60)" rad/s"`
`=40pi" rad/s"`
The angular acceleration of the engine
`=4pi" rad/s"^(2)`