Four identical hollow cylinderical columns of mild steel support a big structure of mass 50,000 kg. the inner and outer radii of each column are 30 and 60 cm respectively. Assuming the load distribution to be uniform, calculate the copressional strain of each column.

Explanation

Load on each column, `F=(50,000)/(4)` kgwt
`=(50,000xx9.8)/(4)N`
`A=pi(r_(2)^(2)-r_(1)^(2))=(22)/(7)[(0.60)^(2)-(0.30)^(2)]`
`=(22)/(7)0.27m^(2)`
Compression strain `=((F)/(A))/(y)=(F)/(Ay)`
`=(50,000xx9.8)/(4xx((22)/(7)xx0.27)xx2.0xx10^(11))`
`=7.21xx10^(-7)`.