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A piece of copper having a rectangular c...

A piece of copper having a rectangular cross-section of `15.2mmxx19.1mm` is pulled in tension with 44,500 N force, producing only elastic deformation. Calculate the resulting strain ?

Text Solution

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Here, `A=15.2xx19.2xx10^(-6)m^(2),F=44,`
`500N,eta=42xx10^(9)Nm^(-2)`
Strain`=("Stress")/("Modulus of elasticity")`
`=((F)/(A))/(eta)=(F)/(Aeta)=(44500)/((15.2xx19.2xx10^(-6))xx42xx10^(9))`
`=3.65xx10^(-3)`.
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