How much should be pressure on a litre of water be changed to compress it by 0.10% ?

Explanation

Here, `V=1` litre=`10^(-3)m^(3),`
`DeltaV//V=0.10//100=10^(-3)`
`B=(PV)/(DeltaV) or P=B(DeltaV)/(V)`
`=(2.2xx10^(9))xx10^(-3)=2.2xx10^(6)pa`.