Home
Class 11
MATHS
Find the equation of the plane passing t...

Find the equation of the plane passing through the point `bara =2bari +3barj-bark " and perpendicular to the vector " 3bari-2barj-2bark` and the distance of this plane from the oringin.

Text Solution

Verified by Experts

The correct Answer is:
`(2)/(sqrt(17))` units.
Promotional Banner

Topper's Solved these Questions

  • PRODUCT OF VECTORS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERCISE 5(a) III|4 Videos

  • PRODUCT OF VECTORS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERCISE 5(b) I|14 Videos

  • PRODUCT OF VECTORS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise SOLVED PROBLEMS|46 Videos

  • PAIR OF STRAIGHT LINES

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERCISE - 4(c) III. |3 Videos

  • PROPERTIES OF TRIANGLES

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise TEXTUAL EXERCISES ( EXERCISE - 10(b) ) III.|11 Videos

Similar Questions

Explore conceptually related problems

The perpendicular distance from origin to the plane passing through the point bara = 2bari +3barj -bark " and perpendicular to the vector " 3bari -2barj-2bark is

Equation of a plane passing through the point A (3,-2,1) and perpendicular to 4bari+7barj-4bark is

The component vector of 4bari-4barj-7bark " perpendicular to " bari-2barj-bark is

The perpendicular distance from origin to the plane passing through the points 2bari -2barj +bark, 3bari +2barj-bark, 3bari -barj-2bark is

If bara " is perpendicular to " bari+barj+ bark " then the vector " bara is

Find the equation of the plane passing through the line of intersection of the planes barr.(bari+barj+bark) =1 and barr.(2bari+3barj-bark)+4 =0 and parallel to X-axis.

Show that the equation of plane passing through the points with position vectors 3bari-5barj-bark,-bari+5barj+7bark and parallel to the vector 3bari-barj+7bark is 3x+2y-z=0

Find the vector equation of the plane passing through the intersection of the planes barr.(bari +barj+bark) = 6 and barr. (2bari+3barj+bark) = -5 " and the point " (1,1,1) .