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cos100^@.cos40^@+sin100^@.sin40^@=…….....

`cos100^@.cos40^@+sin100^@.sin40^@`=……..

Text Solution

Verified by Experts

The correct Answer is:
`1/2`
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Simplify cos 100^(@) cos 40^(@) +sin 100^(@) sin 40^(@)

Simplify cos 100^(@) cos 40^(@) + sin 100^(@) sin 40^(@) .

Knowledge Check

  • cos20^(@)cos40^(@)-sin5^(@)sin25^(@)=

    A
    0
    B
    `(sqrt(3)+1)/4`
    C
    `(sqrt(3)-1)/2`
    D
    `(sqrt(3)-1)/4`

  • cos70^(@)+sin40^(@)=

    A
    `sin10^(@)`
    B
    `cos10^(@)`
    C
    `tan10^(@)`
    D
    `cot 10^(@)`

  • cos20^(@)cos40^(@)cos60^(@)cos80^(@)=

    A
    `1//2`
    B
    `1//4`
    C
    `1//8`
    D
    `1//16`

    • Similar Questions

    Explore conceptually related problems

    S.T cos340^(@) . Cos40^(@)+sin200^(@).sin140^(@)=(1)/(2)

    Prove that cos20^(@)cos40^(@)-sin5^(@)sin25^(@)=(sqrt(3)+1)/4

    Show that cos 340^(@) cos 40^(@)+sin 200^(@) sin 140^(@) = 1/2 .

    Find the values of the following : Tan((pi)/(4)+theta).Tan((pi)/(4)-theta) Sin1140^(@).cos40^(@)-cos780^(@).sin750^(@)

    Prove that cos 20^(@) cos 40^(@) - sin5^(@) sin 25^(@) = (sqrt(3)+1)/(4) .

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