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The Cartesian equation of the sides BC,C...

The Cartesian equation of the sides BC,CA, AB of a triangle are respectively `u_(1)=a_(1)x+b_(1)y+c_(1)=0, u_(2)=a_(2)x+b_(2)y+c_(2)=0` and `u_(3)=a_(3)x+b_(3)y+c_(3)=0`. Show that the equation of the straight line through A bisectig the side `bar(BC)` is `(u_(3))/(a_(3)b_(1)-a_(1)b_(3))=(u_(2))/(a_(1)b_(2)-a_(2)b_(1))`

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The correct Answer is:
`(u_(2))/((a_(2)b_(1)-a_(1)b_(2)))`
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