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A particle is moving in a straight line so that after t seconds its distance is s (in cms) from a fixed point on the line is given by `s= f(t)=8t+t^3.` Find the velocity at time t= 2sec (ii) the initial velocity can acceleration at t=2 sec

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The correct Answer is:
`(i) t=2` is `8+3(4)=20 cm//sec`.
(ii) `(t=0)` is `8 cm//sec`.
(iii) `t=2` is `6(2)=12 cm//sec^(2)`.
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