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On the curve y=x^(2), find a point at wh...

On the curve `y=x^(2)`, find a point at which the tangent is parallel to the chord joining (0,0) and (1,1).

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The correct Answer is:
The corresponding poin on the curve is ``((1)/(2), (1)/(4))`.
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VIKRAM PUBLICATION ( ANDHRA PUBLICATION)-APPLICATION OF DERIVATIVES-Exercise-10(h)
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