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Find the slope of the normal to the curv...

Find the slope of the normal to the curve x=1 -a sin `theta` , y = b `cos^(2) theta ` at `theta= (pi)/(2)` .

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The correct Answer is:
`(-a)/(2b)`
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VIKRAM PUBLICATION ( ANDHRA PUBLICATION)-APPLICATION OF DERIVATIVES-Exercise-10(b)
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