A particle moving along a straight line ...

A particle moving along a straight line has the relation `s=t^(3)+2t+3`, connecting the distance s describe by the particle in time t. Find the velocity and acceleration of the particle at t=4 sec.

Text Solution

Verified by Experts

The correct Answer is:

`24 "units"//"sec"^(2)`

Promotional Banner

Promotional Banner

Topper's Solved these Questions

APPLICATION OF DERIVATIVES
VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Exercise-10(f)|12 Videos
APPLICATION OF DERIVATIVES
VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Exercise-10(g)|16 Videos
APPLICATION OF DERIVATIVES
VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Exercise-10(d)|8 Videos
ADDITION OF VECTORS
VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Exercise - 4 (b) |11 Videos
DIFFERENTIATION
VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Exercise-9(d)|15 Videos

Similar Questions

Explore conceptually related problems

A particle moving along a straight line has the relation s =t^2 +3, connecting the distance s described by the particle in time 1. Find the velocity and acceleration of the particle at t=4 seconds.

A particle is moving along a straight line according to the law s=16+48t-t^3 . The distance travelled by the particle before coming to rest at an instant is

The distance 's' described by a particle in t seconds is given by s=ae^t+be^-t . The velocity at any time t is

The distance travelled by a particle in time t is gicen by s=t^3-2t^2-3t+5 . The velocity of the particle when t=2 sec is

A particle moves along a straight line according to the equation s = 8 cos 2t + 4sint. The initial velocity is

If the distance s travelled by a particle in time t is given by s=t^2-2t+5 , then its acceleration is

The distance described by a particle in t seconds is given by s=ae^t+be^-t . The acceleration is

A particle is moving in a straight line with the relation between the time and the distance in such a way that s=t^3-9t^2+24t-18 . The value of its velocity when the acceleration is zero is

VIKRAM PUBLICATION ( ANDHRA PUBLICATION)-APPLICATION OF DERIVATIVES-Exercise-10(e)

At time t, the distance s of a particle moving in a straight line is g...
Text Solution
|
If y=x^4 then find the average rate of change of y between x= 2 and x=...
Text Solution
|
A particle moving along a straight line has the relation s=t^(3)+2t+3,...
Text Solution
|
The distance-time formula for the motion of a particle along a straigh...
Text Solution
|
The displacement s of a particle travelling in a straight line in t se...
Text Solution
|
The volume of a cube is increasing at the rate of 8cm^3//sec. How fast...
Text Solution
|
A stone is dropped into a quiet lake and ripples move in circles at th...
Text Solution
|
The radius of a circle is increasing at the rate of 0.7 cm/s. What is ...
Text Solution
|
A balloon which always remains spherical on inflation is being inflate...
Text Solution
|
The radius of an air bubble is increasing at the rate of 1/2 cm/sec. A...
Text Solution
|
Assume that an object is launched upward at 980m/seclis position would...
Text Solution
|
Let a kind of bacteria grow by t^(3) (t in sec). At what time the rate...
Text Solution
|
Suppose we have a rectangular aquarium with dimensions of length 8m, w...
Text Solution
|
A container is in the shape of an inverted cone has height 8m and radi...
Text Solution
|
The total cost C(x) in Rupees associated with the production of x unit...
Text Solution
|
The total revenue in rupees received from the sale os x units of a pro...
Text Solution
|
A point P is moving on the curve y = 2 x^(2) . The x coordinate of P ...
Text Solution
|