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In a population of 100 rabbits 40 are sh...

In a population of 100 rabbits 40 are short eared. Short ears are recessive to long ears. There are only two alleles for this gene. Long eared are 60 which are in 1:1 ratio of homozygous and heterozygous. Find out the dominant allelic frequency?.

Text Solution

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Number of rabbits, in the population with Hardy-Weinberg equilibrium = 100.
Number of dominant homozygous. long eared rabbit = 24
Frequency of homozygous dominánt long eared rabbitts `(P^(2))=(1)/(100)xx24=0.24`
Frequency of dominent allele (P) = 0.49.
Frequency of recessive allele = q = 1 – 0.49 = 0.51
`.: 0.51 ` is the frequency of recessive allele in the population.
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