Two blocks `m_(1)=`4 kg and `m_(2)=2` kg connected by a weightless rod on a plane having inclination of `37^(@)` the coefficient of friction of `m_(1)` and `m_(2)` with the inclined plane are `mu=0.25` each. Then the common accleration of the two blocks and the tension in the rod are

Two blocks m_(1) = 4 kg and m_(2) = 2 kg connected by a weightless rod slide down a plane having an inclination of 37^(@) . The coefficient of dynamic friction of m_(1) and m_(2) with the inclined plane are mu_(1) = 0 .75 and mu_(2) = 0 . 25 respectively Find the common acceleration of the two blocks and tension in the rod Take is 37^(@) = 0.6 and cos 37^(@) = 0 .8 .

Two blocks of masses m, = 4 kg and m, = 2 kg connected by a massless rod slide down on an inclined plane of inclination 37 degree as shown in figure. If coefficient of friction of m_1 and m_2 with inclined plane are mu_1 = 0.75 and mu_2 = 0.25 respectively, then tension (T) in the rod is (g = 10 ms^-2)

Two blocks of masses m_(1)=1 kg and m_(2)=2 kg are connected by a string and side down a plane inclined at an angle theta=45^(@) with the horizontal. The coefficient of sliding friction between m_(1) and plane is mu_(1)=0.4, and that between m_(2) and plane is mu_(2)=0.2. Calculate the common acceleration of the two blocks and the tension in the string.

A rod of mass M and length L lies on an incline having inclination of theta = 37^(@) . The coefficient of friction between the rod and the incline surface is mu = 0.90 . Find the tension at the mid point of the rod.

The coefficient of friction between m_(2) and inclined plane is mu (shown in the figure). If (m_(1))/(m_(2))=sin theta then

Two blocks of masses 4 kg and 2 kg are in contact with each other on an inclined plane of inclination 30^(@) as shown in the figure . The coefficient of friction between 4 kg mass and the inclined plane is 0.3 , whereas between 2 kg mass and the plane is 0.2 . find the contact force between the blocks .

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

A block of mass m slides down an inclined plane of inclination theta with uniform speed. The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is