The centre of mass of two masses m & m' moves by distance `(x)/(5)` when mass m is moved by distance x and m' is kept fixed. The ratio `(m')/(m)` is

The centre of mass of a system of two particle of masses m_1 and m_2 is at a distance d_1 from m_1 and at a distance d_2 from mass m_2 such that.

Where will be the centre of mass on combining two masses m and M(M gt m) ?

The centre of mass of a system of two particles of masses m_(1) and m_(2) is at a distance d_(1) from m_(1) and at a distance d_(2) from mass m_(2) such

The position of centre of mass of a system consisting of two particles of masses m_(1) and m_(2) seperated by a distance L apart , from m_(1) will be :

A pair of stars rotates about their centre of mass One of the stars has a mass M and the other has mass m such that M =2m The distance between the centres of the stars is d (d being large compared to the size of either star) . The ratio of kinetic energies of the two stars (K_(m) //K_(M)) is .

Consider a system of two particles having masses m_(1) and m_(2) . If the particle of mass m_(1) is pushed towards the centre of mass of particles through a distance d , by what distance would the particle of mass m_(2) move so as to keep the mass centre of particles at the original position?