If and `alpha`-paricle of mass m, charged q and velocity v is incident on a nucleus charge Q and mass m, then the distance of closest approach is

When an alpha- particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze' its distance of closest approach from the nucleus depends on m as :

When an alpha particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach form the nucleus depends on m as

When an a-particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze', its distance of closest approach from the nucleus depends on v as:

A charged particle of mass m and charge q is kept initially at rest on a frictionless surface. Another charged particle of mass 4m and charge 2q starts moving with velocity v towards it. Calculate the distance of the closest approach for both the charged particles.

If an alpha -particle is incident directly towards a nucleus then it will stop when the distance between them is the distance of closest approach. Which of these is correct?

Figure shows a charge +Q clamped at a point in free space. From a large distance another charge particle of charge -q an.d mass m is thrown toward +Q with an impact parameter d as shown with speed v. Find the distance of closest approach of the two particles.

A beam of specific kind of particles of velocity 2.1 xx 10^7 m//s is scattered by a gold (Z = 79) nuclei. Find out specific charge (charge/mass) of this particle if the distance of closest approach is 2.5 xx 10^-14 m .