A photon of energy hv is absorbed by a free electrons of a metal having work function `phi lt hv`

A photon of energy hv is absorbed by a free electron of a metal having work- function phi lt hv . Choose the correct option(s).

A phot of energy h upsilon is absorbed by a free electron of a metal having work function phi lt h upsilon

A when a photon of energy hv is incidnet on an electron in a metal of work function phi ( lt hv) , the electron will not necesserily come out of the metal . R : work function is the minimum energy required to liberate an electron out of a metal . So some electons may require more energy for their liberation .

The light rays having photons of energy 1.8 eV are falling on a metal surface having a work function 1.2 eV . What is the stopping potential to be applied to stop the emitting electrons ?

A photon of energy 7 eV is incident on a metal surface having the work function of 3.75 eV. What is the stopping potential ?

When photons of energy hv fall on a metal plate, having a work function W, the maximum kinetic energy of the ejected photo electrons is K. What will be the maximum K.E. of the ejected photo electrons, from the same plate if the frequency of incident radiation is doubled ?

A photon energy 3.4 eV is incident on a metal having work function 2 eV . The maximum K.E. of photoelectrons is equal to

Two differenct photons of energies, 1 eV and 2.5 eV, fall on two identical metal plates having work function 0.5 eV, Then the ratio of maximum KE of the electrons emitted from the two surface is -

A beam of light of wavelength lambda is incident on a metal having work function phi and placed on a metal having work function phi and placed in a magnetic field B. The most energetic electrons emitted perpendicular to the field are bent in circular arcs of radius R. Then

When photons of energy hv are incident on the surface of photosensitive material of work function hv_0 , then