A charged oil drop is suspended in a uniform filed of `3xx10^4 v//m` so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge `=9.9xx10^-15kg` and `g=10m//s^2`)

A charged ball of mass 8.4xx10^(16) kg is found to remain suspended in a uniform electric field of 2xx10^(4) Vm^(-1) . Calculate the charge on the ball. Given g = 10 m//s^(2)

If an oil drop of weight 3.2xx10^(-13) N is balanced in an electric field of 5xx10^(5) Vm^(-1) , find the charge on the oil drop.

In the figure shown a ball is suspended from the ceiling of a room in a uniform electric field of magnitude 2xx10^(4) V/m . If the mass of the ball is 25 g and the charge on the ball is 3muC . The angle theta is (g=9.8ms^(-2))

8 equally charged drops are combined to form a big drop. If the potential on each drop is 10 V, then the potential of the big drop will be

A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is 9.6xx10^(-16) kg the charge on it and excess number of electrons on the particle are respectivly (g=10m//s^(2))