A force of 6.4 N stretches a vertical spring by 0.1 m. The mass (in kg) that must be suspended from the spring so that it oscillates with a time period of `(pi)/(4)` second.

A force of 6.4N streches a vertical spring by 0.1m The mass that must be supended from the spring so that it oscilation with a time period of pi//4 second

A force of 6.4 N stretches a vertical spring by 0.1m. Find the mass that must be suspended from the spring so that it oscillates with a period of pi//4 second.

When a mass of 1 kg is suspended from a spring, it is stretched by 0.4m. A mass of 0.25 kg is suspended from the spring and the spring is allowed to oscillate. If g=10 m//s^(2) , then its period of oscillation will be

If the period of oscillation of mass M suspended from a spring is one second, then the period of 4M will be

A mass suspended from a spring of spring constant k is made to oscillate with a time period T. Now, the spring is cut into three equal parts and the mass is suspended from one of the parts. What will be the new time period of oscillations?

A body of mass m is suspended from three springs as shown in figure. If mass m is displaced slightly then time period of oscillation is

The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm . The period of oscillation

The scale of a spring balance reading from 0 to 10 kg is 0.25 m long. A body suspended from the balance oscillates vertically with a period of pi//10 second. The mass suspended is (neglect the mass of the spring)

The period of oscillation of a mass M suspended from a spring of spring constant K is T. the time period of oscillation of combined blocks is