The linear density of a thin rod of length 1m lies as `lambda = (1+2x)`, where x is the distance from its one end. Find the distance of its center of mass from this end.

The density of a linear rod of length L varies as rho=A+Bx where x is the distance from theleft end. Locate the centre of mass.

If the linear density of a rod of length L varies as lambda = A+Bx , find the position of its centre of mass .

The linear mass density of a thin rod AB of length L varies from A to B as lambda (x) =lambda_0 (1 + x/L) . Where x is the distance from A. If M is the mass of the rod then its moment of inertia about an axis passing through A and perpendicualr to the rod is :

The density of a thin rod of length l varies with the distance x from one end as rho=rho_0(x^2)/(l^2) . Find the position of centre of mass of rod.

If the linear density (mass per unit length) of a rod of length 3 m is proportional to x , where x , where x is the distance from one end of the rod, the distance of the centre of gravity of the rod from this end is.

The mass per unit length of a non - uniform rod of length L is given mu = lambda x^(2) , where lambda is a constant and x is distance from one end of the rod. The distance of the center of mas of rod from this end is

The mass per unit length of a non-uniform rod of length L is given by mu= lamdaxx2 ​, where lamda is a constant and x is distance from one end of the rod. The distance of the center of mass of rod from this end is :-

The mass per unit length of a non- uniform rod OP of length L varies as m=k(x)/(L) where k is a constant and x is the distance of any point on the rod from end 0 .The distance of the centre of mass of the rod from end 0 is

Find centre of mass of given rod of linear mass density lambda=(a+b(x/l)^2) , x is distance from one of its end. Length of the rod is l .

A heavy metallic rod of non-uniform mass distribution, is hanged vertically from a rigid support. The linear mass density varies as lambda_((x))=k xx x where x is the distance measured along the length of rod, from its lower end. Find extension in rod due to its own weight.