Let `alpha, beta in R` such that `lim_(x ->0) (x^2sin(betax))/(alphax-sinx)=1` . Then `6(alpha + beta)` equals

Let alpha,beta in R such that lim_(x rarr0)(x^(2)sin(beta x))/(alpha x-sin x)=1* Then 6(alpha+beta) equals

Let alpha, beta in R " be such that " lim_( x to 0) (x^(2)sin (beta x))/(ax - sin x) = 1."Then,"6(alpha+beta)"equals"

If lim_(x rarr0)(x^(2)sin(beta x))/(alpha x-sin x)=1, when write the value of 18(alpha+2 beta)

The value of lim_(x to 0) ("sin" alpha X - "sin" beta x)/(e^(alphax) - e^(beta x)) equals

The value of lim_(x rarr0)(sin alpha x+sin beta x)/(e^(alpha x)-e^(beta x)) equals

If cot(alpha+beta)=0, then sin(alpha+2 beta) is equal to

lim_(x rarr0)(e^(alpha x)-e^(beta x))/(sin alpha x-sin beta x)=

If alpha,beta in(-(pi)/(2),0) such that (sin alpha+sin beta)+(sin alpha)/(sin beta)=0 and (sin alpha+sin beta)(sin alpha)/(sin beta)=-1 and lambda=lim_(n rarr oo)(1+(2sin alpha)^(2n))/((2sin beta)^(2n))