The force of interaction between two charges `q_(1)=6 mu C` and `q_(2)=2 mu C`is `12N` .If charge `q=-2 mu C` is added to each of the charges,then the new force of interaction is

Two point charges +6 mu C and +16 mu C repel each other with a force of 120N. If a charge of -8 mu C is added to each of them, then force between them will becomes

An attractive force of 5 N is acting between two charges of + 2muC and - 2 mu C placed at some distance. If the charges are mutually touched and placed again at the same distance , what will be the new force, between them ?

Two point charge +2 C and +6 C repel each other with a force of 12 N . If a charge of -2 C is given to each other of these charges , the force will now be

Find the equivalent capacitance between P and Q if C_1 = 6 mu F and C= 9 mu F

Two balls carrying charges + 7 muC and -5 mu C attract each other with a force F. If a charge -2 mu C is added to both, the force between them will be :-

Two point charge q_(p)=+2 mu C and q_(Q)=-2 mu C are placed at a distance of 10cm in air/vacuum. (a) Calculate the electric field intensity along the center of line joining the two chages. (b) If a test charge q_(R)=-1.2times10^(-9)C is placed at center of the PQ write the value of force acting on test charge q_(R) and its direction.

Two point charges q_(1) = 4 mu C and q_(2) = 9 mu C are placed 20 cm apart. The electric field due to them will be zero on the line joining them at distamce of

Two small balls carrying charges +9 mu C" and -4 mu C attract each other with a force "F" .If a charge of -5 mu C is added to each one of them,then the force between the balls would become