Suppose a population A has 100 observations 101, 102, ...., 200, and another population B has 100 observations 151, 152, ..., 250. If `V_(A)` and `V_(B)` represent the variances of the two populations respectively, then show that `(V_(A))/(V_(B))` =

Suppose a population A has 100 observations 101,102,................,200 and another population B has 100 observations 151,152,........250. If V_A and V_B represent the variances of the two populations respectively,then V_A/V_B is (a) 1 (b) 9/4 (c) 4/9 (d) 2/3

The displacement - time graph for two particles A and B is as follows. The ratio (v_(A))/(v_(B)) is

The p.d (V_(B)-V_(C) between two point from C to B

Four capacitors and two batteries are connected as shown in the diagram. If V_(a) and V_(b) denote the potentials of the points 'a' and 'b' then .

Two particles of mass m_(A) and m_(B) and their velocities are V_(A) and V_(B) respectively collides. After collision they interchanges their velocities, then ratio of m_(A)/m_(B) is

IF V_(A)andV_(B) are the input voltages (either 5 V or 0 V) and V_(o) is the output voltage then the two gates represented in the following circuits (A) and (B) are :

Figure shows two ships moving in x-y plane with velocity V_(A) " and "V_(B) . The ships move such that B always remains north of A . The ratio (V_(A))/(V_(B)) is eqal to -