Radius of an electron moving in a circle in constant magnetic field is two times that of an `alpha` particle in the same field. Then de-Broglie wavelength of electrons is x-times of the `alpha`-particle Here x is

The radius of and alpha -particle moving in a circle in a constant magnetic field is half of the radius of and electron moving in circular path in the same field. The de Broglie wavelength of alpha -particle is n times that of the electron. Find n (an integer).

Protons and alpha -particles have the same de Broglie wavelength. What is same for both of them?

A proton, a neutron, an electron and an alpha -particle have same energy. Then their de-Broglie wavelengths compare as

The energy of an alpha -particle, whose de-Broglie wavelength is 0.004Å , will be:

Find the ratio of velocities of proton and alpha -particle if the de Broglie wavelengths of both the particles is same.

The energy of an alpha -Particle, whose de-broglie wavelength is 0.004 Å will be -

What will be the ratio of de - Broglie wavelengths of proton and alpha - particle of same energy ?

A proton of energy E is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the same path will be equal to