Let `f(x)=ax^(2)-b|x|` , where a and b are constant . Then at x=0 , f(x) has

Let f(x)=ax^(2)-b|x|, where a and b are constants.Then at x=0,f(x) has a maxima whenever a>0,b>0 a maxima whenever a>0,b 0,b 0,b<0

Let f(x) =ax^(2) -b|x| , where a and b are constants. Then at x = 0, f (x) is

A function is defined as f(x) = ax^(2) – b|x| where a and b are constants then at x = 0 we will have a maxima of f(x) if

Let f(x)=a+b|x|+c|x|^(4), where a,b and c are real constants.Then,f(x) is differentiable at x=0, if a=0 (b) b=0( c) c=0(d) none of these

Let f(x)=a+b|x|+c|x|^(4), where a,b, and c are real constants.Then,f(x) is differentiable at x=0, if a=0( b) b=0 (c) c=0( d) none of these

Let f(x)=a+b|x|+c|x|^(2) , where a,b,c are real constants. The, f'(0) exists if

Let f(x)=ax^(2)+bx+c where a,b and c are real constants.If f(x+y)=f(x)+f(y) for all real x and y, then

Let f(x)=(2x+1)/(x),x!=0, where

A function has the form f(x)=ax+b, where a and b are constants. If f(2)=1" and "f(-3)=11 , the function is defined by