A particle executes S.H.M. given by the equation y = 0.45 sin 2t where y is in meter and t is in second. What is the speed of the particle when its displacement is 7.5 cm?

A particles executes SHM according to the equation y = 2 sin 2pit , where y is displacement in m and t is time in s. The distance covered by the particle in 4 s of its motion is

The displacement of a particle executing S.H.M. is given by y = 10 sin [6t + (pi)/(3)] where y is in metres and t is in seconds. Then the initial displacement and velocity of the particle is

A particle has displacement y given by y =3 sin (5 pi t + pi) , where y is in meter and t is in second. What are frequency and period of motion ?

A particle executes SHM represented by the equation 10y=01sin50pit, where the displacement y is in metre and time t in second. Find the amplitude and frequency of the particle.

Position-time relationship of a particle executing simple harmonic motion is given by equation x=2sin(50pit+(2pi)/(3)) where x is in meters and time t is in seconds. What is the position of particle at t=0.5s ?

The displacement of a particle is represented by the equation, s=3 t^3 =7 t^2 +4 t+8 where (s) is in metres and (t) in seconds . The acceleration of the particle at t=1 s is.

A particle executes a linear S.H.M. given by y= 0.5 "sin" 100 (metre). Its amplitude and frequency given in cm and hertz are

A particle of 0.8 kg is executing S.H.M., Its amplitude is 1.0 metre and time period is 11/ 7 seconds. The velocity of the particle at the instant when its displacement is 0.6 metre will be :

The equation of motion of a particle starting at t=0 is given by x=5sin(20t+π/3) , where x is in centimeter and t is in second. When does the particle come to rest for the second time?

The x and y coordinates of a particle at any time t are given by x = 2t + 4t^2 and y = 5t , where x and y are in metre and t in second. The acceleration of the particle at t = 5 s is