ABCD is a rectangle in which AB= 9cm, BC=6cm. P is a point in CD such that PC = xcm, then the value of x when `AP^2 + BP^2` is minimum is

ABCD is a rectangle in which AB=10cms,BC=8cms.A point P is takes on AB such that PA=x Then the minimum value of PC^(2)-PD^(2) is obtained when x=

ABCD is a rectangle,PC=9cm,BP=15cm,AB=14cm. Then the angles of /_APB are such that:

Construct a rectangle ABCD in which side BC=5 cm and diagonal BD=6.2cm.

ABCD is a trapezium in which AB ||CD, AB =20cm, BC =10 cm, CD =10 cm and AD =10 cm . Find /_ADC