Work done in converting 1 g of ice at `-10^@C` into steam at `100^@C` is

Heat required to convert 1 g of ice at 0^(@)C into steam at 100 ^(@)C is

What is the amount of heat required (in calories) to convert 10 g of ice at -10^(@)C into steam at 100^(@)C ? Given that latent heat of vaporization of water is "540 cal g"^(-1) , latent heat of fusion of ice is "80 cal g"^(-1) , the specific heat capacity of water and ice are "1 cal g"^(-1).^(@)C^(-1) and "0.5 cal g"^(-1).^(@)C^(-1) respectively.

How much work in joule is done in producing heat necessary to convert 10g of ice at -5^(@)C into steam at 100^(@)C ? Given specificheat of ice =0.5 cal g^(-1).^(@)C^(-1) , latent heat of steam = 540 cal g^(-1) .

Find the quantity of heat required to convert 2gm of ice at -10C into steam at "100C

The amount of heat (in calories) required to convert 5g of ice at 0^(@)C to steam at 100^@C is [L_("fusion") = 80 cal g^(-1), L_("vaporization") = 540 cal g^(-1)]

Find the amount of heat enegy required to convert 100 g of ice at -10^(@)C into stea at 120^(@)C . (Take S_(ice)=0.5" cal "g^(-1).^(@)C^(-1),S_(W)=1" cal "g^(-1)^(@)C^(-1),S_("Steam")=0.5" cal "g^(-1).^(@)C,L_(f)=80" cal "g^(-1),L_(V)=540" cal "g^(-1) )

Calculate the amount of heat required to convert 10 g ice at -10^@C into steam at 120^@C at normal pressure. If heat is supplied uniformly at the rate 50cal//s , sketch variation temperature with time

How much work is needed to convert 5g of ice at -3^(@)C to steam at 100^(@)C ? (Sp. Heat capacity of ice =500 cal kg^(-1)K^(-1) sp. Latent heat of fusion of ice =80xx10^(3) cal kg^(-1) sp. Latent heat of vaporization of water =536xx10^(3)calkg^(-1) , and J=4.2 joules per calorie)