The maximum value of index of refraction of a material of a prism which allows the passage of light through it when the refracting angle of prism is A is

The maximum value of index of refraction of a material of a prism which allows the passage of light through it when the refracting angle of the prism is A , is

The maximum value of refractive index of a prism which permits the transmission of light through it when the refracting angle of the prism is 90^@, is given by

For the refraction of light through a prism

The angle of minimum deviation of a prism of refractive index sqrt(3) is equal to its refracting angle. Then the refracting angle of that prism is

The angle of minimum deviation of a prism of refractive index sqrt(3) is equal to its refracting angle. Then the refracting angle of the prism is

The maximum refractive index of a material, of a prism of apex 90^(@) , for which light may be transmitted is

If the refractive index of material of a prism is sqrt3 , then angle of minimum diviation of the prism, which is equilateral is

The refractive angle of a prism is 60^(@) . What is the angle of minimum deviation, if the refractive index of the material of the prism is sqrt2 ?

(a) If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then find the angle of incidence. (b) A ray of light passes through an equilateral prism such that the angle of emergence is equal to the angle of incidence and each is equal to 3//4^(th) of the angle of prism. Find the angle of deviation. (c) The refracting of a prism is A and the refractive index of the material of the prism is cotA//2 . Find the angle of deviation. (d) The angle of a prism is 60^@ . What is the angle of incidence for minimum deviation? The refractive index of the material of the prism is sqrt2 .