A ball of radius r and density r falls freely under gravity through a distance h before entering water. Velocity of ball does not change even on entering water. If viscosity of water is `eta` the value of h is given by
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A small ball of radius 'r' falls freely under gravity through a distance 'h' before entering a tank of water. If after entering the water, the velocity of ball does not change, the 'h' is proportional to

A small ball of radius 'r' falls freely under gravity through a distance 'h' before entering a tank of water. If after entering the water, the velocity of ball does not change, the 'h' is proportional to

In an experiment to verify Stokes law , a small spherical ball of radius r and density rho falls under gracvity throught a distance h in air before entering a tank of wate . If the terminal velocity of the ball inside water is same as its velocity just befor entering the water surface , then the value of h is proportional to : ( ignore viscosity of air ) .

A spherical ball of radius 3xx10^(-4) m and density 10^(4)kg//m^(3) falls freely under gravity through a distance h before entering a tank of water. If after entering the water the velocity of the ball does not change, find h the viscosity of water is 9.8xx10^(-6)N-s//m^(2)

A spherical ball of radius 3.0xx10^(-4) m and density 10^(4)(kg)/(m^(3)) falls freely under gravity through a distance H=nxx500m before entering a tank of water. If after enerting the water the velocity of the ball does not change, then find n. viscosity of water is 10xx10^(-6)(N-s)/(m^(2)) , g=10(m)/(s)

A metal ball ofradius 10^(-4) m and density 10^4 kg//m^3 falls freely under gravity through a distance 'h' and enters a tank of water. It is found that after entering the water, the velocity of ball does not change. What is the value of h? [eta "for water "10^(-5)" Pas ",g=10m//s^2" and "orh_("water")=10^3kg//m^3 ]

A ball of density o and radius r is dropped on the surface of a liquid of density p from certain height. If speed of ball does not change even on entering in liquid and viscosity of liquid is r). then the height from which ball dropped is

A solid ball of density half that of water falls freely under gravity from a height of 19.6 m and then enters water. Neglecting air resistance and viscosity effect in water, the depth up to which the ball will go is (g= 9.8 m//s^(2))