when two displacements represented by `y_(1) = a sin(omega t)` and `y_(2) = b cos (omega t)` are superimposed the motion is

When two displacement represented by y_(1) = a sin (omega t) and y_(2) = b cos (omega t) are superimposed, the motion is

Two wave are represented by equation y_(1) = a sin omega t and y_(2) = a cos omega t the first wave :-

Two waves represented by y_1 =a sin omega t and y_2 =a sin (omega t+phi) "with " phi =(pi)/2 are superposed at any point at a particular instant. The resultant amplitude is

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

The displacements of two intering lightwaves are y_(1) = 4 sin omega t and y_(2) = 3 cos(omega t) . The amplitude of the resultant wave is ( y_(1) and y_(2) are in CGS system)

Two light waves are represented by y_(1)=a sin_(omega)t and y_(2)= a sin(omega t+delta) . The phase of the resultant wave is

Two simple harmonic motions are represented by y_(1)= 10 "sin" omega t " and " y_(2) =15 "cos" omega t . The phase difference between them is

Two waves are given by y_(1) = a sin (omega t - kx) and y_(2) = a cos (omega t - kx) . The phase difference between the two waves is