Find the magnitude of uniform electric field E of which the direction is shown in figure if an electron entering with velocity l00m/s making `30^(@)` comes out making `60^(@)` , after a time numerically equal to m/e ofelectron where m is mass ofelectron and e is electronic charge :

A uniform electric field of strength e exists in a region. An electron (charge -e, mass m) enters a point A with velocity V hat(j) . It moves through the electric field & exits at point B. Then :

A uniform electric field of strength E exists in region. A electron enters a point A with velocity v as shown. It moves through the electric field and reaches at point B. Velocity particle at B is 2v at 30^@ with x-axis . Then

A charge of magnitude 3e and mass 2m is moving electric field vecE . The acceleration imparted to the charge is

Drift speed of electron inside the metallic conductor is v_(A) = eE^(y) m^(z) tau (here, e = electronic charge, E = electric field, m = mass of electron and tau = time relaxation). Find the value of y .

The gyromagnetic ratio of an electron of charge e and mass m is equal to

An electron (mass m_(e ) )falls through a distance d in a uniform electric field of magnitude E. , The direction of the field is reversed keeping its magnitudes unchanged, and a proton(mass m_(p) ) falls through the same distance. If the times taken by the electrons and the protons to fall the distance d is t_("electron") and t_("proton") respectively, then the ratio t_("electron")//t_("proton") .

An electron is moving initially with velocity v_o hati+v_ohatj in uniform electric field vec E=-E_0 hatk . If initial wavelength of electron is lambda_0 and mass of electron is m. Find wavelength of electron as a function of time.

An uniform electric field E exists along positive x-axis. The work done in moving a charge 0.5 C through a distance 2 m along a direction making an angle 60^(@) with x-axis is 10 J. Then the magnitude of electric field is