Starting from the origin, a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 25% of the total energy?

Starting from the origin a body osillates simple harmonicall with a period of 2 s. A fter what time will its kinetic energy be 75% of the total energy?

Starting from the mean position a body oscillates simple harmonically with a period of 2 s.

Starting from the origin a body oscillates simple harmonically with a period of 2s . After time (1)/(x) second willthe kinetic energy be 75% of its total energy , then value of x is

A loaded vertical spring executes simple harmonic oscillations with period of 4 s. The difference between the kinetic energy and potential energy of this system oscillates with a period of

A particle executing simple harmonic motion with time period T. the time period with which its kinetic energy oscilltes is

A particle executes simple harmonic motion of ampliltude A. At what distance from the mean position is its kinetic energy equal to its potential energy?

A particle is executing simple harmonic motion with frequency f . The frequency at which its kinetic energy changes into potential energy is

For Simple Harmonic Oscillator, the potential energy is equal is equal to kinetic energy

A body starting from mean position is executing simple harmonic motion. Its time . period is 24 s. After 4 s, its velocity is pi" "m//s then its path length is