A concave lens of glass, refractive index 1.5 has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a

A convax lens of glass ,refractive index 1.5 ,has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75 ,it wuill behaves as a (A)convergent lens of focal length 3.5R (B)convergent lens of focal length 3.0R (C)divergent lens of focal length 3.5R (D)divergent lens of focal length 3.0R

A convex lens made up of glass of refractive index 1.5 is dippedin turn (i) in a medium of refractive index 1.65 (ii) in a medium of refractive index 1.33 (a) Will it behave as converging or diverging lens in the two cases ? (b) How will its focal length changes in the two media ?

A double convex lens of + 5 D is made of glass of refractive index 1.5 with both faces of equal radii of curvature. Find the value of curvature.

A diverging lens of refractive index 1.5 and focal length 15 cm in air has same radii of curvature for both sides. If it is immersed in a liquid of refractive index 1.7 , calculate focal length of the lens in liquid.

The adjacent figure shows a thin plano-convex lens of refractive index mu_1 and a thin plano-concave lens of refractive index mu_2 , both having same radius of curvature R of their curved surfaces. The thin lens of refractive index mu_3 has radius of curvature R of both its surfaces. This lens is so placed in between the plano-convex and plano-concave lenses that the plane surfaces are parallel to each other. The focal length of the combination is

A thin convex lens made of glass of refractive index 3//2 has a power of 5 D. When it is immersed in a liquid of refractive index mu , it behaves like a divergent lens of focal length 1 m. Calculate the refractive index of the liquid.

A thin glass (refractive index 1.5) lens has optical power of -5D in air. Its optical power in a liquid medium with refractive index 1.6 will be