If one end of a diameter of the circle `x^(2)+y^(2)-4x-6y+11=0` is (3, 4), then find the coordinates of the other end of the diameter.

If one end of a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (3,2), the other end is

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.

The length of the diameter of the circle x^(2)+y^(2)-4x-6y+4=0 is -

If one end of a diameter of the circle . x^(2) + y^(2) - 4x - 6y + 11 = 0 is (8,4), show that co -ordinates of the other end are (-4, 2) .

If one end of the a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (3,2), then find the other end of the diameter.

If one end of a diameter of the circle 3x^(2)+3y^(2)-9x+6y+5=0 is (1,2), then the other end is

If (2, 3, 5) is one end of a diameter of the sphere x^(2)+y^(2)+z^(2)-6x-12y-2z+20=0 , then the coordinates of the other end of the diameter are

One of the diameter of the circle x^(2)+y^(2)-2x+4y-4=0 , is

If one end of a diameter of the circle 2x^(2)+2y^(2)-4x-8y+2=0 is (-1,2), then the other end of the diameter is