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A given mass of a gas occupies 572 cm^3 ...

A given mass of a gas occupies `572 cm^3` at `13^@c` and 725 mm Hg pressure. What will be its volume at `24^@C` and 792 mm Hg pressure

Text Solution

Verified by Experts

`P_1 = 725mm Hg, V_1=572 cm^3,`
`T_1 = (273+13) K= 286 K,`
`P_2 = 792mm Hg, V-2 =? Cm^3,`
`T_2 = (273+24) K= 297 K`
applying the equation
`(P_1 V_1)/T_1 = (P_2 V_2)/T_2`
substiuting the values
`(725xx572)/286 = (792xxV_2)/297`
`or V_2 (725xx572xx297)/(286xx792) = 543.75cm^3`
the required volume of gas is `543.75cm^3`
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