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A boy standing in front of a wall at a d...

A boy standing in front of a wall at a distance of 85 m produces 2 claps per second. He notices that the sound of his clapping coincides with the echo. The echo is heard only once when clapping is stopped. Calculate the speed of sound.

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To solve the problem, we need to calculate the speed of sound based on the information provided. Here’s the step-by-step solution: ### Step 1: Understand the situation The boy is standing 85 meters away from a wall and produces 2 claps per second. He hears the echo of his clap coincide with the sound of his next clap. ### Step 2: Determine the time interval for the echo Since the boy produces 2 claps per second, the time interval between each clap is: \[ ...
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