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A person standing between two vertical cliffs and 640 m away from the nearest cliff, produces sound. He hears the first echo after 4 s and the second echo 3 s later. Calculate :
the speed of sound in air,

Text Solution

Verified by Experts


First echo is heard from the nearest cliff.
Let d be the distance of the nearest cliff 1 from the person. Total distance travelled by the sound in going and then coming back `= 2d_1 = 2 xx 640 m = 1280 m `
Time taken t = 4 s
` therefore ` Speed of sound `=("total distance travelled "2d_1)/("time taken t") `
` = ( 1280 m)/( 4 s) = 320 m s^(-1)`
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