A certain sound has a frequency of 256 hertz and a wavelength of 1.3 m.
(a) Calculate the speed with which this sound travels.
(b)What difference would be felt by a listener between the above sound and another sound travelling at the same speed, but of wavelength 2.6 m?

Explanation

For second sound, `V = 332.8 m s^(-1) , lamda = 2.6 m`
` therefore ` Frequency `f =(V )/(lamda) = (332.8 )/( 2.6 )= 128 Hz`
The frequency of the first sound is 256 Hz while that of the second sound is 128 Hz. The first sound is of higher pitch than the second sound. Hence to the listener, the first sound will be shriller than the second sound.