Three resistors of 6 `Omega `, 3` Omega ` and 2`Omega ` are connected together so that the total resistance is greater than 6 `Omega `, but less than 8 `Omega `. Draw a diagram to show this arrangement and calculate its total resistance.

Explanation

To solve the problem, we need to connect three resistors (6 Ω, 3 Ω, and 2 Ω) in such a way that the total resistance is greater than 6 Ω but less than 8 Ω. Here’s how we can do it step by step:

### Step 1: Understanding the Arrangement
To achieve a total resistance greater than 6 Ω but less than 8 Ω, we can connect the 6 Ω resistor in series with a combination of the 3 Ω and 2 Ω resistors connected in parallel.

### Step 2: Drawing the Circuit Diagram
1. Draw a battery (or power source).
2. Connect the 6 Ω resistor in series with the parallel combination of the 3 Ω and 2 Ω resistors.
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