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Two resistors of 4 Omega and 6 Omega ar...

Two resistors of 4 `Omega ` and 6 `Omega` are connected in parallel. The combination is connected across a 6 V battery of negligible resistance. (i) Draw a circuit diagram. (ii) Calculate :the current through each resistor

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### Step-by-Step Solution: **(i) Draw a Circuit Diagram:** 1. **Identify Components**: We have two resistors, R1 = 4 Ω and R2 = 6 Ω, and a battery of 6 V. 2. **Connect Resistors in Parallel**: In a parallel circuit, both resistors are connected across the same two points, meaning they share the same voltage. 3. **Draw the Battery**: Place the battery at the top, indicating the positive and negative terminals. 4. **Connect the Resistors**: Draw the two resistors in parallel below the battery. Connect one terminal of each resistor to the positive terminal of the battery and the other terminal of each resistor to the negative terminal of the battery. ...
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Two resistors of 4 Omega and 6 Omega are connected in parallel. The combination is connected across a 6 V battery of negligible resistance. (i) Draw a circuit diagram. (ii) Calculate :the current through the battery

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Knowledge Check

  • Three resistors 2Omega, 4Omega and 5Omega are combined in parallel. This combination is connected to a battery of emf 20V and negligible internal Resistance. The total current drawn from the battery is

    A
    10A
    B
    15A
    C
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    D
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    B
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    C
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    D
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