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Fig. shows two resistors A of 4 Omega ...

Fig. shows two resistors A of `4 Omega ` and B of 6 ` Omega ` joined in series to a battery of e.m.f. 12 V and internal resistance 2 `Omega` . Calculate :

the p.d. across the resistor B,

Text Solution

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Given : `R_A = 4 Omega , R_B = 6 Omega , epsi = 12 V , r= 2 Omega `
` t=1 ` ,minute ` = 60 s `
p.d across the resistor `B = I R_B`
` = 1.0 xx 6 = 6.0 V `
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