A battery of e.m.f. 15 V and internal resistance 3` Omega ` is connected to two resistors 3 `Omega` and 6 `Omega ` connected in parallel. Find :
the current in 3 `Omega ` resistor,

Explanation

To solve the problem of finding the current in the 3Ω resistor connected to a battery with an e.m.f. of 15V and an internal resistance of 3Ω, we can follow these steps:

### Step 1: Understand the Circuit Configuration
We have a battery with an e.m.f. of 15V and an internal resistance of 3Ω. This battery is connected to two resistors (3Ω and 6Ω) that are arranged in parallel.

### Step 2: Calculate the Equivalent Resistance of the Parallel Resistors
The formula for the equivalent resistance (R_net) of two resistors in parallel (R1 and R2) is given by:
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