Home
Class 10
PHYSICS
An electric bulb of resistance 500 ohm d...

An electric bulb of resistance 500 ohm draws current 0.4 A from the source. Calculate :
the power of bulb

Text Solution

AI Generated Solution

To calculate the power of the electric bulb, we can use the formula for electrical power. The power (P) consumed by an electrical device can be calculated using the formula: \[ P = V \times I \] Where: - \( P \) is the power in watts (W), - \( V \) is the voltage in volts (V), - \( I \) is the current in amperes (A). ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    ICSE|Exercise EXERCISE-8(C) MULTIPLE CHOICE TYPE)|2 Videos

  • CALORIMETRY

    ICSE|Exercise EXERCISE-11(B) (NUMERICALS)|15 Videos

  • ELECTRO-MAGNETISM

    ICSE|Exercise EXERCISE-10 (C) NUMERICALS |1 Videos

Similar Questions

Explore conceptually related problems

An electric bulb of resistance 500Omega , draws a current of 0.4 A. Calculate the power of the bulb and the potential difference at its end.

A bulb is connected to a battery of p.d. 4 V and internal resistance 2.5 Omega . A steady current of 0.5 A flows through the circuit. Calculate : the energy dissipated in the bulb in 10 minutes.

A bulb is connected to a battery of p.d. 4 V and internal resistance 2.5 Omega . A steady current of 0.5 A flows through the circuit. Calculate : the total energy supplied by the battery in 10 minutes,

An electric bulb is connected to a 220 V generator. The current is 0.50 A . What is the power of the bulb ?

A bulb is connected to a battery of p.d. 4 V and internal resistance 2.5 Omega . A steady current of 0.5 A flows through the circuit. Calculate : the resistance of the bulb,

100 W,220V bulb is connected to 110V source. Calculate the power consumed by the bulb.

The resistance of the filament of an electric bulb changes with temperature. If an electric bulb rated 220 volt and 100 watt is connected (220 xx 0.8) volt sources, then the actual power would be

A torch bulb when cold has a resistance 1 Omega . It draws a current 300 mA, when glowing from a source of potential differences 3 V. Calculate the resistance of the bulb when glowing and explain the reason for the difference in resistance.

If electric bulbs having resistances in the ratio 2 : 3 are connected in parallel to a voltage sources of 220 V. The ratio of the power dissipated in them is

An electric bulb is designed to draw P_(0) power at V_(0) voltage. If the voltage is V , it drawas power. Then

Home
Profile