A bulb is connected to a battery of p.d. 4 V and internal resistance 2.5 `Omega `. A steady current of 0.5 A flows through the circuit. Calculate :
the energy dissipated in the bulb in 10 minutes.

Explanation

To solve the problem, we need to calculate the energy dissipated in the bulb when a steady current flows through it for a specified time. Here’s a step-by-step solution:

### Step 1: Identify the given values
- Potential difference (V) = 4 V
- Internal resistance of the battery (r) = 2.5 Ω
- Current (I) = 0.5 A
- Time (t) = 10 minutes = 600 seconds

...