If 190 MeV energy is released due to fission of each nucleus of U-235, what mass of U-235 undergoes fission per hour in a reactor of power 300 MW ?
Take 1 a.m.u. `= 1.66 xx 10^-27 kg`.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Convert the energy released per fission from MeV to Joules
The energy released during the fission of each U-235 nucleus is given as 190 MeV. We need to convert this energy into Joules.

\[ \text{Energy (E)} = 190 \, \text{MeV} \times 1.6 \times 10^{-19} \, \text{J/MeV} = 3.04 \times 10^{-11} \, \text{J} \]
...