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A pulley system with a velocity ratio 4 ...

A pulley system with a velocity ratio 4 is used to lift a load of 300 kgf to a vertical height of 10 m by applying an effort of 100 kgf downwards.
ind the efficiency of the pulley system and the work done by the effort.

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Velocity ratio = number of pulleys = 4
Mechanical advantage = `"load"/"effort"="300 kgf"/"100 kgf"=3`
Efficiency = `"mechanical advantage"/"velocity ratio"=3/4=0.75`
`therefore" "3/4=(300kgfxx10m)/(W_("effort"))`
`therefore" "W_("effort")=400kgfxx10m=(400xx10)Nxx10m=4xx10^4J`
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