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A square plate of side 10 m is placed ho...

A square plate of side 10 m is placed horizontally 1 m below the surface of water. The atmospheric pressure is `1.013xx10^(5)Nm^(-2)`. Calculate the total thrust on the plate.
(Density of water `rho=10^(3)kg m^(-3), g=9.8ms^(-2))`

Text Solution

Verified by Experts

Given, `h=1m , rho=10^(3) kg m^(-3)`, `g=9.8 ms^(-2)`
Atmospheric pressure `P_(0)=1.013xx10^(5)Nm^(-2)`
area of plate `=10mxx10m=10^(2)m^(2)`.
Total pressure at a point below the surface of water = atmospheric pressure + pressure due to the column of water
`P_(0)+hrhog`
`=(1.013xx10^(5))+(1xx10^(3)xx9.8)`
`=1.111xx10^(5)Nm^(-2)`
`:.` Total thrust on the plate = Pressure `xx` Area of plate
`=(1.111xx10^(5))xx10^(2)`
`=1.111xx10^(7)N`.
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