Home
Class 9
PHYSICS
A U tube is first partially filled with ...

A U tube is first partially filled with mercury. Then water is added in one arm and an oil is added in the other arm. Find the ratio of water and oil columns so that mercury level is same in both the arms of U tube. Given : Density of water `=10^(3)kg m^(-3)` , density of oil `=900kg m^(-3)`.

Text Solution

AI Generated Solution

To solve the problem of finding the ratio of the heights of the water and oil columns in a U-tube so that the mercury levels remain the same in both arms, we can follow these steps: ### Step 1: Understand the Pressure Balance For the mercury levels to be the same in both arms of the U-tube, the pressure exerted by the water column in one arm must equal the pressure exerted by the oil column in the other arm. ### Step 2: Write the Pressure Equations The pressure exerted by a liquid column is given by the formula: \[ P = \rho g h \] ...
Promotional Banner

Topper's Solved these Questions

  • PRESSURE IN FLUIDS AND ATMOSPHERIC PRESSURE

    ICSE|Exercise Exercise-4(A)|31 Videos

  • PRESSURE IN FLUIDS AND ATMOSPHERIC PRESSURE

    ICSE|Exercise Exercise-4(A)multiple choice |4 Videos

  • MOTION IN ONE DIMENSION

    ICSE|Exercise EXERCISE -2 (C) ( Multiple choice type :) |17 Videos

  • PROPAGATION OF SOUND WAVES

    ICSE|Exercise EXERCISE -8(B) (Multiple choice type)|3 Videos

Similar Questions

Explore conceptually related problems

A simple U tube contains mercury to the same level in both of its arms. If water is poured to a height of 13.6 cm in one arm, how much will be the rise in mercury level in the other arm ? Given : density of mercury = 13.6 xx 10^3 "kg m"^(-3) and density of water = 10^3 "kg m"^(-3) .

The mass of 1 litre of water is 1 kg. Find the density of water in kg m^(-3)

Calculate the molarity of water if its density is 1000 kg m^(-3)

The pressure at a point in water is 10 N//m^(2) . The depth below this point where the pressure becomes double is (Given density of water = 10^(3) kg m^(-3) , g = 10 m s^(-2) )

A U-tube is partially filled with water. Oil which does not mix with water is next poured into one side, until water rises by 25 cm on the other side. If the density of oil 0.8g//cm^(3) . The oil level will stand higher than the water by

Find the pressure exerted below a column of water, open to the atmosphere, at depth (i) 5 m (ii) 20 m (Given, density of water = 1 xx 10^(3)"kg m"^(-3), g = 10 m s^(-2) )

Find the pressure exerted below a column of water, open to the atmosphere, at depth (i) 10 m " " (ii) 30 m (Given, density of water =1xx10^(3)kgm^(-3), g =10 ms^(-2))

Calculate the pressure due to a water column of height 100 m. (Take g=10 ms^(-2) and density of water =10^(3)kg m^(-3)) .

An open U-tube contains mercury. When 11.2 cm of water is poured into one of the arms of the tube, how high does the mercury rise in the other arm from its initial level ?

Two capillary tubes of diameters 3.0 mm and 6.0 mm are joined together to form a U -tube open at both ends. If the U -tube is filled with water, what is the difference in its levels in the two limbs of the tube ? Surface tension of water at the temperature of the experiment is 7.3xx10^(2)N//m . Take the angie of contact to be zero and density of water to be 10^(3)kg//m^(3) ( g=9.8m//s^(2) )