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A mercury barometer reads 75cm. Now 3 cm...

A mercury barometer reads 75cm. Now `3 cm^(3)` of atmospheric air is introduced into the tube. The mercury falls to a height of 65 cm and the length of air column above the mercury is found to be 15 cm Calculate the cross-sectional area of the barometer tube.

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To solve the problem step by step, we will use the information provided in the question and apply Boyle's Law, which states that the product of pressure and volume for a given mass of gas is constant, provided the temperature remains unchanged. ### Step 1: Identify the given data - Initial height of mercury in the barometer (h1) = 75 cm - Height of mercury after introducing air (h2) = 65 cm - Volume of air introduced (V1) = 3 cm³ - Length of the air column above mercury (L) = 15 cm ...
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